Find the rate in which both balls make one full rotation around the track.
Ball A:
It takes 30 seconds for Ball A to make a full rotation.
Ball B:
It takes 20 seconds for Ball B to make a full rotation.
Find the least common multiple of 20 and 30 to find the time at which they'll meet.
Multiples of 20: {20,40,60}
Multiples of 30: {30,60}
60 is the least common multiple of both 20 and 30.
The balls will meet again at
60 seconds.
= (x^18y^24)/(x^2y^2)
Simplified = x^16y^22
The last answer is correct (x^16y^22)
Edited answer: The number is: "- 6" .
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8 (8 + x) = 16 ;
in which "x" represents the number for which to be solved ;
8*8 + 8*x = 16 .
Edit: 64 + 8x = 16 ;
Subtract "64" from each side of the equation:
Edit: 64 + 8x − 64 = 16 <span>− 64 ;
to get: 8x = </span>- 48 ;
Divide EACH SIDE of the equation by "8" ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ;
Edit: 8x / 8 = -48 / 8 ;
Edit: x = - 6 .
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The number is: "- 6" .
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Let us check our answer, by plugging in "-6" for "x" in the original equation:
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8 (8 + x) = 16 ;
→ 8 [8 + (-6) ] =? 16 ?? ;
→ 8 (8 − 6 ) =? 16 ?? ;
→ 8 (2) =? 16 ?? ;
→ 16 = ? 16 ?? Yes!
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Well, notice the composite is really just 4 triangles atop sitting on top of 4 rectangles, and all of them area stacked up at the edges.
so, for the rectangle's sides,
front and back are two 6x3 rectangles
left and right are two 6x3 rectangles
the bottom part is a 6x6 rectangle
now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.
now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.
so, just get the area of all those rectangles and the triangles, sum them up and that's the
surface area of the composite,
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Use Pythagoras' theorem:
a^2 + b^2 = c^2
Sub the values in:
10^2 + 10^2 = c^2
200 = c^2
Square root to find the answer:
c = 14.14
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- Ally ✧
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