Answer:
D
Step-by-step explanation:
Given
| 2 - 4n | - 4 = 34 ( add 4 to both sides )
| 2 - 4n | = 38
The absolute value function always returns a positive value but the expression inside can be positive or negative, that is
2 - 4n = 38 OR -(2 - 4n) = 38
subtract 2 from both sides
- 4n = 36 ( divide both sides by - 4 )
n = - 9
OR
-(2 - 4n) = 38
- 2 + 4n = 38 ( add 2 to both sides )
4n = 40 ( divide both sides by 4 )
n = 10
As a check
Substitute these values into the equation and if both sides are equal then they are the solutions.
n = - 9
| 2 + 36 | - 4 = | 38 | - 4 = 38 - 4 = 34 = right side
n = 10
| 2 - 40 | - 4 = | - 38 | - 4 = 38 - 4 = 34 = right side
Thus the solutions are { - 9, 10 } → D
The answer is 8.
3 times 2 times 8 equals 48.
You ran 6 miles on the treadmill on Monday.
Y=x-3, because when you do rise over run you get 3/3 which is equal to 1, so that means 1x, or just x. it intercepts into -3 on both axis’s so that is where the -3 comes from. glad to help :)
Answer:
93
Step-by-step explanation:
Key :
A1 = Algebra 1
A2 = Algebra 2
Alright so basically lets first look at the info they gave us :
We have 5 more than twice as many students taking A1 than we do A2.
We have 44 students taking A2.
And we need to find the least amount of students that could be taking A1.
So we need to take the amount of students taking A2 (44) and double it to find the amount taking A1.
So we can do 44 x 2 = 88 to get this.
But the problem also states there is 5 more then twice the number of students taking A2.
So we have that 88 but now we just need to add 5 to make up for them telling us that in the problem.
So :
88 + 5 = 93
Our final answer and least amount of students taking A1 is 93 students.
