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11Alexandr11 [23.1K]
3 years ago
14

What is the value of -2(x+5)?​

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0
I thinks 5 because -2(x) = -2x and -2(5)=-10
So -2x=-10
-10/-2=5
X=5
Crazy boy [7]3 years ago
5 0

Answer:

- 2(x + 5) =  (- 2x - 10)

<h2>(-2x-10) is the right answer.</h2>
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URGENT ! what is the common difference of the arithmetic series 14+12+10+8
k0ka [10]

Explanation:

An arithmetic sequence has a common difference, meaning you use addition or subtraction to get from term to term, and each term in the sequence is an equal distance apart.

A geometric sequence has a common ratio, meaning that you use multiplication or division to get from term to term.

If you look at this sequence:

14-2 = 12

12-2 = 10

10-2 = 8

8 -2 = 4

etc.

Because you are subtracting 2 each time, 2 is the common difference, and the sequence is arithmetic.

6 0
3 years ago
Diego was asked to plot these points: (-50, 0), (150, 100), (200, -100), (350, 50), (-250, 0). What interval could he use for ea
ivolga24 [154]

Answer:

Interval of 50 on both axis

Step-by-step explanation:

Given

(x_1,y_1) = (-50,0)

(x_2,y_2) = (150,100)

(x_3,y_3) = (200,-100)

(x_4,y_4) = (350,50)

(x_5,y_5) = (-250,0)

There are several ways to do this, but I will use the observation method, since the dataset is small.

Considering the x-coordinates

x = \{-50,150,200,350,-250}

Each element of the data set is a multiple of 50.

Hence, an interval of 50 can be used on the x-axis

Considering the y-coordinates

y = \{0,100,-100,50,0\}

Each element of the data set is a multiple of 50.

Hence, an interval of 50 can be used on the y-axis

<em>So, an interval of 50 can be used on both axes</em>

5 0
3 years ago
Need some help please
denis23 [38]
The median of this problem is 84
5 0
2 years ago
Read 2 more answers
ILL GIVE MEDAL AND BRAINLIST AWNSER TO whoEVER IN THE FIRST!!!!Roland's heart beats 495 times in 6 minutes. At that rate, how ma
Sonbull [250]

<em>Answer,</em>

C. 1650

<em>Explanation,</em>

<em>495/6 = 82.5</em>

<em>82.5 x 20 = </em><em>1650</em>


<u><em>Hope this helps :-)</em></u>

7 0
3 years ago
In a garden club, 90% i ladie. The number of ladie i 12 more than 3 time the number of gentlemen. How many ladie and how many ge
wariber [46]

In the garden club there are 18 ladies and 2 gentlemen.

Given, In a garden club, 90% is ladies.

The number of ladies is 12 more than 3 times the number of gentlemen.

Let the total members be, x

the number of ladies be, l and the number of gentlemen be, g

according to the question,

l = 90x/100

l = 9x/10

also, l = 12 + 3g

g = (l - 12)/3

as, l + g = x

9x/10 + (9x/10 - 12)/3 = x

9x/10 + 9x/30 - 4 = x

36x/30 - 4 = x

6x/30 = 4

x = 20

so, ladies be, l = 9x/10 = 18

and gentlemen be, g = 20 - 18 = 2

Hence, in the garden club there are 18 ladies and 2 gentlemen.

Learn more about Linear Equations here brainly.com/question/25869125

#SPJ4

4 0
1 year ago
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