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olasank [31]
3 years ago
12

Hello!? what's 3 + 3

Mathematics
2 answers:
astra-53 [7]3 years ago
7 0

Answer:

6

Step-by-step explanation:

if you have 3 apples and 3 banannas in all you have 6 fruits in total :)

3 bugs+ 3 ladybugs= 6 bugs

<h3><em>Hope this helps lol :)</em></h3>

rjkz [21]3 years ago
4 0

Answer:

6

Step-by-step explanation

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If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
Solve this system using matrices:
sweet [91]

Answer:

Step-by-step explanation:

A system of linear equations is one which may be written in the form

a11x1 + a12x2 + · · · + a1nxn = b1 (1)

a21x1 + a22x2 + · · · + a2nxn = b2 (2)

.

am1x1 + am2x2 + · · · + amnxn = bm (m)

Here, all of the coefficients aij and all of the right hand sides bi are assumed to be known constants. All of the

xi

’s are assumed to be unknowns, that we are to solve for. Note that every left hand side is a sum of terms of

the form constant × x

Solving Linear Systems of Equations

We now introduce, by way of several examples, the systematic procedure for solving systems of linear

equations.

Here is a system of three equations in three unknowns.

x1+ x2 + x3 = 4 (1)

x1+ 2x2 + 3x3 = 9 (2)

2x1+ 3x2 + x3 = 7 (3)

We can reduce the system down to two equations in two unknowns by using the first equation to solve for x1

in terms of x2 and x3

x1 = 4 − x2 − x3 (1’)

1

and substituting this solution into the remaining two equations

(2) (4 − x2 − x3) + 2x2+3x3 = 9 =⇒ x2+2x3 = 5

(3) 2(4 − x2 − x3) + 3x2+ x3 = 7 =⇒ x2− x3 = −1

8 0
3 years ago
Read 2 more answers
The concentration of dichlorodiphenyltrichloroethane (DDT - an infamous pesticide) in Lake Michigan has been declining exponenti
mojhsa [17]

Answer: A) y=13e^{-0.1359t}

              B) H = 5.10

              C) Yes

Step-by-step explanation: <u>Exponential</u> <u>Decay</u> <u>function</u> is a model that describes the reducing of an amount by a constant rate over time. Generally, it is written in the form: y(t)=Ce^{rt}

A) C is initial quantity, in this case, the initial concentration of DDT. To determine r, using the data given:

y(t)=Ce^{rt}

2.22=13e^{13r}

e^{13r}=0.1708

Using a natural logarithm property called <em>power rule:</em>

13r=ln(0.1708)

r=\frac{ln(0.1708)}{13}

r=-0.1359

The decay function for concentration of DDT through the years is y(t)=13e^{-0.1359t}

B) The value of H is calculated by y=C(0.5)^{\frac{t}{H} }

2.22=13(0.5)^{\frac{13}{H} }

(0.5)^{\frac{13}{H} }=0.1708

Again, using power rule for logarithm:

\frac{13}{H} log(0.5)=log(0.1708)

\frac{13}{H} =\frac{log(0.1708)}{log(0.5)}

\frac{13}{H} =2.55

H = 5.10

Constant H in the half-life formula is H=5.10

C) Using model y(t)=13e^{-0.1359t} to determine concentration of DDT in 1995:

y(24)=13e^{-0.1359.24}

y(24) = 0.5

By 1995, the concentration of DDT is 0.5 ppm, so using this model is possible to reduce such amount and more of DDT.

8 0
2 years ago
Please show your work
Crank

Answer:

y=17

Step-by-step explanation:

So the shape is a square, which means 1 is equal to 90 degrees. So, 4y+22=90

When you solve, you get 17:

4y=68

y=17

6 0
3 years ago
1. y = 3(x - 4)2 - 2
oksano4ka [1.4K]

Answer:

y = 3x - 12

Step-by-step explanation:

8 0
3 years ago
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