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Wewaii [24]
3 years ago
9

Which theorem(SSS, SAS, ASA, or AAS) would prove the triangles congruent?

Mathematics
2 answers:
Neko [114]3 years ago
7 0

Answer:

SSS

Step:

I think it might be this not very sure

neonofarm [45]3 years ago
5 0

Answer:

ASA

Step-by-step explanation:

A and C are congruent (angle) and then ad and dc are also (side) and they both have a right angle 90 (angle)

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24

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Find the 12th term of the arithmetic sequence 2x + 8,6x + 5, 10x + 2, ...
lawyer [7]

Answer: The 12th term is 46x -25

Step-by-step explanation:

It is increasing by 4x and decreasing by 3 through each term, this represents the d. a1 has already been identified as 2x +8, so you just have to write down the formula and the solve form there by plugging in the 12 in (n-1) to find the answer.

8 0
3 years ago
A. Use the​ one-mean t-interval procedure with the sample​ mean, sample​ size, sample standard​ deviation, and confidence level
PtichkaEL [24]

Answer:

a) (17.227, 22.773)

b) 2.773

c) 2.773

Step-by-step explanation:

Given:

Sample size, n = 25

Standard deviation, s = 4

Sample mean, x' = 20

Level of significance, a = 0.98 = 1 - 0.98 = 0.02

The degrees of freedom, df, for a t-distribution = n - 1 = 25 - 1 = 24

Using the t table, the Critical value = t_\alpha _/_2, _d_f = t_0_._0_2_/_2, _2_4 = t_0_._0_1_, _2_4 = 3.4668

Margin of error, E = t_\alpha _/_2, _d_f * \frac{\sigma}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

Limits of 98% confidence interval, we have:

Lower limit : x' - M.E = 20 - 2.773 = 17.227

Upper limit: x' + M.E = 20 + 2.773 = 22.773

Therefore, (17.227, 22.773) is 98% confidence interval.

b) Let's the margin of error by taking half the length of the confidence interval.

Since we are to use half the length of CI, we have:

M.E = \frac{22.773 - 17.227}{2} = 2.773

c)M.E = t_\alpha _/_2, _d_f *s/\sqrt{n}

= t * \frac{s}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

4 0
3 years ago
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