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kifflom [539]
2 years ago
5

Dan has twice as many stickers as cam does. If Dan gives cam 15 of his stickers he will have 22 more than cam. How many stickers

does each boy have? HURRY
Mathematics
1 answer:
sleet_krkn [62]2 years ago
7 0
I’m not very sure but it might be 74 because if you add 15 to 22 you get 37 and 37 x 2= 72..? sorry if i’m wrong :(
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Find the surface area of the rectangular prism
Umnica [9.8K]

Answer:

185.68 cm3

Step-by-step explanation:

SA = 2 (L x W) + 2 (L x H) + 2 (W x H)

     = 2 (8.2 x 3.4) + 2 (8.2 x 5.6) + 2 (3.4 x 5.6)

     = 2 (27.88)      + 2 (45.92)      + 2 (19.04)

     =     55.76       +     91.84         +     38.08

     SA = 185.68 cm3

4 0
3 years ago
How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\
a_1=54 \\
a_4=128 \\ \\
a_n=a_1 \times r^{n-1} \\
a_4=a_1 \times r^3 \\
128=54 \times r^3 \\
\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\
\frac{64}{27}=r^3 \\
\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\
\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\
r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\
a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\
\boxed{a_2=72, a_3=96}
7 0
3 years ago
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Write a real-world problem given the equation 2/3x = 12. Then solve the equation.
LuckyWell [14K]

Answer:

x = 1/18

Step-by-step explanation:

2/3x = 12

multiply both sides by 3x

2/3x(3x) = 12(3x)

2 = 36x

x = 1/18

5 0
3 years ago
Use the functionſ to answer the question. f () = 3x2 - 7x - 32 What is the value of f (-4)? A. -52 B. -12 O c. 44 D. 140 +
cricket20 [7]

Step-by-step explanation:

step 1. please write it f(x) = 3x^2 - 7x -32

step 2. f(-4) = 3(-4)^2 -7(-4) - 32

step 3. f(-4) = 48 + 28 - 32

step 4. f(-4) = 44.

3 0
3 years ago
What is the Lateral area of this prism ?
Mazyrski [523]

Answer:

idk let me go look at it

Step-by-step explanation:

5 0
3 years ago
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