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3 years ago

PLZ HELP ME WILL GIVE BRAINLIEST. THANKYOU!

Mathematics

1 answer:

Maru [420]3 years ago

3 0

Answer:

there is no solution

Step-by-step explanation:

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(8v + 8) (8v^2 + 4v - 8) find the product

mars1129 [50]

Answer:

Answer is below

Step-by-step explanation:

64v^3+96v^2-32v-64

5 0

3 years ago

Read 2 more answers

Please help me with number 14 name the propriety illustrated by the following

ASHA 777 [7]

A. .x -x=0
x+ -x=0
0=0
all real numbers are solutions
b. x-y+(-x)=x-y+(-x)
-y=-y
0=0
x=0/0 0 over 0

6 0

4 years ago

Simplify this expression

Sergeu [11.5K]

Answer:

option 4

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ = $\sqrt{ab}$

Given

(2 - 5 $\sqrt{6}$ ) 3 $\sqrt{2}$ ← distribute parenthesis by 3 $\sqrt{2}$

= 6 $\sqrt{2}$ - 15 $\sqrt{12}$

= 6 $\sqrt{2}$ - 15 $\sqrt{4(3)}$

= 6 $\sqrt{2}$ - 15( $\sqrt{4}$ × $\sqrt{3}$ )

= 6 $\sqrt{2}$ - 15(2 $\sqrt{3}$ )

= 6 $\sqrt{2}$ - 30 $\sqrt{3}$

4 0

4 years ago

A force of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i

Wittaler [7]

Answer: 18.75 lb.ft

Step-by-step explanation:

Given

Force required to stretch spring 8 in. is 18 lb

it can be written

$\Rightarrow F=kx\\\Rightarrow 18=k(8)\\\\\Rightarrow k=\dfrac{18}{8}=\dfrac{9}{2}\ lb/in.$

Work done in stretching from its natural length to 10 in.

$\Rightarrow W=\dfrac{1}{2}kx^2\\\\\Rightarrow W=0.5\times \dfrac{9}{2}\times (10)^2\\\\\Rightarrow W=225\ lb.in.\ or\\\Rightarrow W=18.75\ lb.ft$

8 0

3 years ago

Using the information given, select the correct ending balance.

klemol [59]

Step-by-step explanation:

Simple first we will add previous balance and total deposit

498.03 + 604.28

= 1102. 31

Then we will subtract it by total withdrawals

1102.31 - 599.49

= 502. 82

The ending balance is 502.82

6 0

3 years ago