You can use the Pythagorean Theorem:
a^2+b^2=c^2
x^2+x^2=(7√2)^2
2x^2=49*2 (combine like terms and square the 7√2)
x^2=49 (divide both sides by 2)
x=7 (square root both sides)
So the equation is 2x^2=98 (simplest form) and x=7
Hope this helps
Answer:
you need to use tracing paper for this
The system of equations 6x+4y=14 and 9x+6y=c are linear equations
The value of c that makes the system have infinitely many solutions is 21
<h3>How to determine the value of c?</h3>
The system of equations are given as:
6x+4y=14
9x+6y=c
Divide through the second equation by 3
3x + 2y = c/3
Multiply through by 2
6x + 4y = 2c/3
Subtract the first equation from the above equation
6x - 6x + 4y - 4y = 2c/3 - 14
Evaluate the differences
2c/3 - 14 = 0
Add 14 to both sides
2c/3 = 14
Multiply by 3/2
c = 21
Hence, the value of c that makes the system have infinitely many solutions is 21
Read more about system of equations at:
brainly.com/question/14323743
20,484,163 in expanded form
2 ten million and 0 one million and 4 hundred thousand and 8 ten thousand and 4 one thousand and 1 hundreds and 6 tens and 3 ones.
or
2 x 10,000,000 + 0 x 1,000,000 + 4 x 100,000 + 8 x 10,000 + 4 x 1,000 + 1 x 100 + 6 x 10 + 3 x 1
