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3 years ago

Write three expression that are equivalent to the given expression. 8k+36

Mathematics

2 answers:

Eva8 [605]3 years ago

5 0

Hey there!

“8k + 36”

8: 1, 2,4,8, k

36: 1,2,3,4,6,9,12, 18, 36

GCF: 4

Answer: 4(2k + 9)

Check to see if it gives us the same expression in the question

4(2k + 9)

4(2k) + 4(9)

4(2k) = 8k

4(9) = 36

So to SUM it all up, your ANSWER is:

4(2k + 9) ☑️

Good luck on your assignment and enjoy your day!

~Amphitrite1040

Mazyrski [523]3 years ago

4 0

Answer:

8,000+36 and 8x1000+36 thats the only few i could think of

Step-by-step explanation:

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Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f

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Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval: (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{130}{20} = 6.5$

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

$S.D = \sqrt{\frac{233.5}{19}} = 3.50$

b) Standard Error

$= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826$

c) Point estimate for the mean time required for all college is given by the sample mean.

$\bar{x} = 6.5$

d) 90% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729$

$6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)$

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

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4 years ago

What is 3/8 of 1/4??

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Step-by-step explanation: divid 3/8 and 1/4 together and you get 0.09375

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3 years ago

A groundskeeper needs grass seed to cover a circular field 380 feet in diameter A store sells 70 pound bags of grass seed. One p

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4 bags.........................

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3 years ago

Suppose a graduate program has sent acceptance letters to 45 applicants, but only has enough funding for 30 students. Let the st

gulaghasi [49]

Answer:

the probability that the graduate program will have enough funding for all student that join the program is 0.3653 (36.53%)

Step-by-step explanation:

since each student is independent on others the random variable X= x students of 45 applicants will join the program has a binomial probability distribution

P(X=x)= n!/[(n-x)!*x!]*p^x*(1-p)^x

where

n= total number of students= 45

p= probability that a student join the program= 0.7

x= number of students that join the program

then in order to have enough funding x should not surpass 30 students , then

P(X≤30)= ∑P(X) for x from 1 to 30 = F(30)

where F(30) is the cumulative probability distribution

then from binomial probability tables

P(X≤30)= F(30)= 0.3653 (36.53%)

therefore the probability that the graduate program will have enough funding for all student that join the program is 0.3653 (36.53%)

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3 years ago