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zlopas [31]
3 years ago
7

The diagram shows a right angled triangle.

Mathematics
1 answer:
uysha [10]3 years ago
4 0

Answer:

6 root 2

Step-by-step explanation:

Pythagous Therom

A^2 = B^2 + C^2

B^2 = C^2 - A^2

B^2 = 36 - (2 Root 3)^2

B^2 = 24

B = 2 root 6

Base x Height / 2 for area of Triangle

2 root 3 x root 24 = 12 root 2

12 root 2 / 2 = 6 root 2

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(a) A natural number that is greater than 25 and less than 40
zloy xaker [14]

<u>Step-by-step explanation:</u>

(a) A natural number that is greater than 25 and less than 40

Natural Number : These are numbers starting from 1 or also sometimes from zero and are all positive !  A natural greater than 25 & less than 40 is 30 .

(b) An integer which is less than -5 and a multiple of 2

Integer : An integer is a whole number not a fraction including 0 . It can be positive or negative ! Integer less than -5 and a multiple of 2 is -6.

(c) A rational number between 1 and 2

Rational Number : A number which can be expressed in form of p/q where q is not equal to 0 . A rational number between 1 & 2 is 3/2 .

(d) An irrational number between 8 and 9.​

Irrational Number: A real number which is not rational or can't be written in form of p/q . An irrational number between 8 & 9 is 6\sqrt{2} .

5 0
3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
Open notes test: Relations, Functions and Slope
Karolina [17]

Answer:

I'm not sure what your asking

6 0
3 years ago
How do you simplify this problem?
Yuri [45]

1+tan^2(x) = sec^2(x)

sec^2(x) = 1/cos^2(x)

csc(-x) / 1/cos^2(x) =

cos^2(x) csc(-x)

4 0
3 years ago
Plz answer the question
Bumek [7]
24 were of the questione were correct
3 0
3 years ago
Read 2 more answers
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