Formula for the area of a quarter circle: A = (pi x r^2) / 4
A = (pi x 1^2) / 4
A = 1pi / 4
A = 0.79 square centimeters
Hope this helps! :)
Answer:
Option (1)
Step-by-step explanation:
From the picture attached,
Triangle CAB is a right triangle.
Therefore, m∠1 = 90°
Similarly, m∠ACD = 90°
m∠ACD = m∠ACB + m∠BCD = 90°
= m∠3 + m∠4 = 90°
Since m∠4 = 35°,
m∠3 + 35° = 90°
m∠3 = 90° - 35°
= 55°
In the triangle ABC,
m∠ACB + m∠CBA + m∠BAC = 180° [Property of a triangle]
m∠3 + m∠2 + m∠1 = 180°
55° + m∠2 + 90° = 180°
m∠2 + 145° = 180°
m∠2 = 180° - 145°
= 35°
Since, AB║CD and BC is a transverse,
Therefore, m∠2 = m∠4 = 35° [Alternate interior angles]
Option (1) is the correct option.
The answer to the question is
Answer:
JUST TO START I COMMENT ON THIS SORRY
Step-by-step explanation:
4366+766
5251551=8654
