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3 years ago

Brenda buys a shirt for $40. She has a coupon for 25% off. What is 25% of $40?

Mathematics

2 answers:

tia_tia [17]3 years ago

8 0

Answer:

Step-by-step explanation: hehejejehjejejehehhejehehejehehheehejhehejehejejejejejjejejejejejhhehejejjejejejeejehhehehe

ohaa [14]3 years ago

3 0

Answer:

$10

Step-by-step explanation:

40 X .25 = 10

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Find the area of the part of the paraboloid z = 9 - x^2 - y^2 that lies above the xy-plane.

svetoff [14.1K]

Parameterize this surface (call it $S$ ) by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(9-u^2)\,\vec k$

with $0\le u\le3$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec r_u\times\vec r_v=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then the area of $S$ is

$\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle2\pi\int_0^3u\sqrt{1+4u^2}\,\mathrm du=\boxed{\frac{37\sqrt{37}-1}6\pi}$

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3 years ago

I really need help with this question, can you help?

Varvara68 [4.7K]

Answer:

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Step-by-step explanation:

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3 years ago

A container holds six red marbles and four green marbles. You select two marbles from the container (without replacement) what i

SpyIntel [72]

The Red marble has a 6/10 (60%) chance of gettinv picked while the blue marbles have a 4/10 (40%) chance of getting picked.

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3 years ago

-(1+7x)=6(-7-x)+36 <br> Alg 2

olganol [36]

Let's solve your equation step-by-step.

−(1+7x)=6(−7−x)+36

Step 1: Simplify both sides of the equation.

−(1+7x)=6(−7−x)+36

−7x+−1=(6)(−7)+(6)(−x)+36(Distribute)

−7x+−1=−42+−6x+36

−7x−1=(−6x)+(−42+36)(Combine Like Terms)

−7x−1=−6x+−6

−7x−1=−6x−6

Step 2: Add 6x to both sides.

−7x−1+6x=−6x−6+6x

−x−1=−6

Step 3: Add 1 to both sides.

−x−1+1=−6+1

−x=−5

Step 4: Divide both sides by -1.

−x

−1

−5

−1

x=5

Answer:

x=5

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3 years ago

Question<br> (X-5y/y3)-1=

Ilia_Sergeevich [38]

Answer:

$x = y^3+5y$

Step-by-step explanation:

Complete question

$\frac{x - 5y}{y^3} - 1=0\\$

Required

Solve for x

We have:

$\frac{x - 5y}{y^3} - 1=0$

Collect like terms

$\frac{x - 5y}{y^3} = 1$

Multiply through by $y^3$

$x - 5y = y^3$

Make x the subject

$x = y^3+5y$

8 0

2 years ago