All categories

3 years ago

How is good at statics to help me? Plz

Mathematics

1 answer:

IgorC [24]3 years ago

8 0

Answer:

Overall, if it is a major you can do well and enjoy yourself in, yes, statistics is a great major. Combine it with other majors like finance or economics or research-oriented disciplines like psychology, it'll be really good training for you. If you can't do it, do a minor. If you can't, take some electives.

Step-by-step explanation:

You might be interested in

WILL GIVE BRAINLIEST 50 POINTS

Marat540 [252]

Answer:

I think its 95.0%.But I am not sure about it

4 0

2 years ago

Read 2 more answers

Hurry please!

Kryger [21]

Answer:

We have the equation of the line as : 4x+2y=12

Step-by-step explanation:

Now 4x+2y=12

=> 2y = 12 - 4x

=> y = 6 - 2x

A line with a slope m and y-intercept c can be written as y = mx + c

In the case of y = -2x -...

3 0

2 years ago

Please help me with this question

Alenkasestr [34]

Answer:

$\sqrt{8 + y}$

3 0

3 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago

It’s 11:45 and you have an awesome appointment in 3 hours and 25 minutes. What time is your appointment? Please HELP!

stiks02 [169]

Answer: The time would be 3:00

There are 60 minute per hour. If it is 11:45, it's 25 minutes until 12:10. Once it is 12:10, the next hour (after 50 minutes) would be 1:00. so if you take 11:45 and add the 25 minutes from 3 hours and 25 minutes, it is 12:10 and you are left with 3 hours. 3 hours after 12:10 is 3:10

5 0

3 years ago