Actually the position function with respect to time under constant acceleration is:
a=g
v=⌠g dt
v=gt+vi
s=⌠v
s=gt^2/2+vit+si
So if vi and si are zero then you just have:
s=gt^2/2
Notice that it is not gt^2 but (g/2) t^2
So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...
Anyway....
sf=(a/2)t^2+vit+si
(sf-si)-vit=a(t^2)/2
2(sf-si)-2vit=at^2
a=(2(sf-si)-2vit)/t^2 and if si and vi equal zero
a=(2s)/t^2
Answer:
-6 is the x-coordinate value
Step-by-step explanation:
Mathematically, slope can be calculated as;
m = (y2-y1)/(x2-x1)
For the value of the slope to be undefined, it means that we are actually dividing by zero
For us to be dividing by zero, it actually means that there is no change in the x-value
The unchanging x-value is what has caused us to have an undefined slope value
Since line k and line g are parallel, their slopes are equal and the slope of k is undefined too
So the x-coordinates of the other points that lie on the line that we used in calculating the slope is -6
Answer:
<u>14.96</u>
Step-by-step explanation:
6*84p=504p
504p=£5.04
£20-£5.04=14.96
