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2 years ago

A rectangle has an area of 40 sq units , then length is 6 units greater than the width

Mathematics

1 answer:

devlian [24]2 years ago

6 0

Answer:

A=L*W

Let w be width

L=(w+6)

40=(w+6)*w

40= w^{2} +6w

w^{2} +6w-40=0

w^{2}+10w-4w-40=0

w(w+10)-4(w+10)=0

(w-4)(w+10)=0

w=4

Length= 10 units

Width=4 units

Step-by-step explanation:

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NARA [144]

Answer:

x = -0.17 and x = -5.83

Step-by-step explanation:

We are asked to solve the quadratic equation

$x^2+6\,x+1=0$

We use the quadratic formula using a = 1, b = 6 and c = 1

for a general quadratic equation of the form: $ax^2+bx+c=0$

Then, the solutions are given by;

$x=\frac{-6+/-\sqrt{36-4\,(1)\,(1)} }{2} =\frac{-6+/-\sqrt{32} }{2}$

which produces the two following answers (rounded to two decimals):

x = -0.17 and x = -5.83

8 0

3 years ago

NO LINKS PLZ AND REAL ANSWERS ASAP

ozzi

A & D are the correct answers!

8 0

2 years ago

Hi I need question 5 solved using SOH CAH TOA!

Bond [772]

According to the trigonometric functions, we can see that angle x can be found through the one that involves the adjacent side and the hypotenuse, which in this case is the cos,

$cos(x)=\frac{27}{30}$

then, if we apply the inverse we can find the value of x,

$\begin{gathered} cos^{-1}(cos(x))=cos^{-1}(\frac{27}{30}) \\ x\cong25.8 \end{gathered}$

Answer:

$x\cong25.8$

5 0

1 year ago

When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the future value FV.

In order to see the rule of formation, let's see the value (in $) for the first few years

End of year 0

1,000

End of year 1(capital + interest + new deposit)

1,000*(1.09)+10

End of year 2 (capital + interest + new deposit)

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

End of year 3 (capital + interest + new deposit)

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the sum of a geometric sequence with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The present value PV is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

2 years ago

Matt is making cookies. He adds 3/4 of a cup of sugar to a bowl. He then removes two 1/8 cups of sugar. What best explains how m

irga5000 [103]

Matt has 5/8 cups of sugar left in the bowl

7 0

2 years ago