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Anon25 [30]
4 years ago
5

If the midpoint of line segment what?

Mathematics
1 answer:
ioda4 years ago
3 0

We can use the midpoint formula to find our answer, which is \Bigg(\dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2}\Bigg), where (x_1, y_1) and (x_2, y_2) are endpoints of a line.


In this case, we can substitute information we know into the problem to find our answer. We already know one of the coordinates and what the midpoint is, meaning that we can obtain the expression:

\Bigg(\dfrac{0 + x_2}{2}, \dfrac{4 + y_2}{2}\Bigg) = (-2, 10)


We should now solve our problem by setting the first part of the first coordinate with the first part of our midpoint and by setting the second part of the coordinate with the second part of our midpoint, like this:

\dfrac{0 + x_2}{2} = -2 and \dfrac{4 + y_2}{2} = 10


Now, solve each expression independently:

\dfrac{0 + x_2}{2} = \dfrac{x_2}{2} = -2

x_2 = -4


\dfrac{4 + y_2}{2} = 10

4 + y_2 = 20

y_2 = 16


Our second coordinate, endpoint N, is (-4, 16). The answer is C.

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Vector u has initial points at (21,12) and it’s terminal point at (19,-8). Vector v has a direction opposite that of u. Who’s ma
8_murik_8 [283]

The correct form of vector v expressed as a <em>linear</em> combination of the <em>unit</em> vectors i and j is \vec v = 10\,\hat{i} + 100\,\hat{j}.

<h3>What is the value of a vector with respect to another vector?</h3>

First, we need to determine the value of the vector u by subtracting two vectors whose <em>initial</em> points are at the origin:

\vec u = (19\,\hat{i} - 8\,\hat{j}) - (21\,\hat{i} + 12\,\hat{j})

\vec u = - 2\,\hat{i} - 20\,\hat{j}     (1)

According to the statement, vector v is antiparallel to vector u and its magnitude is five times as the magnitude of vector v, which means that (1) must be multiplied by two scalars:

\vec v = - 1 \,\cdot \, 5\cdot \vec u      (2)

Please notice that antiparallelism is represented by the scalar - 1, whereas the dilation is represented by the scalar 5.

\vec v = 10\,\hat{i} + 100\,\hat{j}

The correct form of vector v expressed as a <em>linear</em> combination of the <em>unit</em> vectors i and j is \vec v = 10\,\hat{i} + 100\,\hat{j}.

<h3>Remark</h3>

The statement presents typing mistakes, correct form is shown below:

<em>Vector u has initial points at (21, 12) and its terminal point at (19, - 8). Vector v has a direction opposite that of u, whose magnitud is five times the magnitud of v. Which is the correct form of vector v expressed as a linear combination of the unit vectors i and j?</em>

To learn more on vectors: brainly.com/question/13322477

#SPJ1

8 0
2 years ago
5/16t=-9
Svetradugi [14.3K]
I'm going to assume that the equation is \frac{5}{16}t = -9 where the 't' is not in the denominator

If that assumption is correct, then we do two things to solve for t. First, we multiply both sides by 16. This undoes the division of 16 on the left side

\frac{5}{16}t = -9

16*\frac{5}{16}t = 16*(-9)

5t = -144

-------------------------------

Then we divide both sides by 5 to undo the multiplication of 5 (note: 5t means 5*t or "5 times t")

5t = -144

\frac{5t}{5} = \frac{-144}{5}

t = -\frac{144}{5}

-------------------------------

So here's what all the steps look like:

\frac{5}{16}t = -9

16*\frac{5}{16}t = 16*(-9)

5t = -144

\frac{5t}{5} = \frac{-144}{5}

t = -\frac{144}{5}

note: -144/5 converts to the decimal value of -28.8 so t = -144/5 is the same as t = -28.8
3 0
4 years ago
Y=-3(x + 5)^2 - 4<br> Convert the equation from vertex formi to standard form.
Stolb23 [73]
I believe in Vertex form it would be (-5,-4)
6 0
2 years ago
How many factors does 1000 have
ololo11 [35]

1,2,4,5,8,10,20,25,40,50,100,125,200,250,500,1000

That is all of its factors so therefore, 1,000 has 16 factors.

8 0
4 years ago
Helpppp? please if possible .&lt;3
marusya05 [52]
Am I too late to answer this
5 0
3 years ago
Read 2 more answers
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