Question

Does anyone know this?

Answer 1

Answer:

The answer is first option i.e

$\triangle ABC \cong \triangle GHJ\ \textrm{angle - side - angle test i.e ASA}$

Step-by-step explanation:

Given:

1. angle ABC = angle GHJ

2. BC = HJ

3. angle BCA = angle HJG

Proof:

In ΔABC and ΔGHJ

$\angle ABC \cong \angle GHJ \ Given\\BC \cong HJ\ \textrm{Given}\\\angle BCA \cong \angle HJG \ \textrm{Given}\\\\\triangle ABC \cong \triangle GHJ\ \textrm{angle - side - angle test i.e ASA}$

Hence proved