Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot.
- Lowest amount of sale made by Latasha = 50
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution
- IQR = Upper Quartile (Q3) - Lower quartile(Q1)
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box)
- Q1 = 150 (starting point of the box)
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box)
- Q1 = 100 (starting point of the box)
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.
Learn more :brainly.com/question/24582786
Answer:
Categorical variable
Step-by-step explanation:
An ordinal variable is a categorical variable for which the possible values are ordered. Please mark me as brainliest.
Hello :) we got similar answers but i believe you made a few distributing mistakes! hopefully my work makes sense, if not i’ll totally try to explain more
p.s i might be too late whoops
p.p.s i’m in a higher grade but i haven’t done this kinda math in a longgg time haha so if you think i did something wrong trust your gut ✌️
2, sin( θ )=6/12=1/2 => theta=30 degrees.
=> triangle is 30-60-90
3.
Cos(45)=sqrt(2)/2
=> x=10*sqrt(2)/2=5sqrt(2)
The second side of a triangular deck is 4 feet longer than the shortest side
(s+4) = the 2nd side
and a third side that is 4 feet shorter than twice the length of the shortest side.
(2s-4) = the 3rd side
If the perimeter of the deck is 48 feet, what are the lengths of the three sides?
s + (s+4) + (2s-4) = 48
Combine like terms
s + s + 2s + 4 - 4 = 48
4s = 48
s = 48/4
s = 12 ft is the shortest side
I'll let you find the 2nd and 3rd sides, ensure they add up to 48
Hope this helps!