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DaniilM [7]
3 years ago
9

I need help with this please​

Mathematics
2 answers:
tatuchka [14]3 years ago
7 0

Answer:

25.<em> </em><em>y=2x+1</em>

26.<em> </em><em>$13</em>

Step-by-step explanation:

25. 2x is the cost each day or the x, and the 1 is the initial fee, I found this because <u>it said one day costs $3 and if I know that one days fee is $2 then I know that the y intercept or the price it starts at also known as a fee is $1</u>. This is also <u>backed up in the 4 day statement</u> saying that 4 days is 9 dollars. I can do 9-1 to take away the fee and 8/2=4 so it is correct.

26. Since I already have the equation I can just plug in the vales and solve. <u>y=2x+1, x=2 or the daily cost so 12+ (the fee) 12+1=13 so</u> <em>$13.</em>

good luck, and have a great day.    :)

Vladimir [108]3 years ago
4 0
For 25 the answer would be y = 2x +
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. A firm produces a commodity and receives $100 for each unit sold. The cost of producing and selling x units is 20x + 0.25x 2 d
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\bf p(x)=-0.25x^2+80x\\\\&#10;-------------------------------\\\\&#10;\textit{ vertex of a vertical parabola, using coefficients}\\\\&#10;\begin{array}{lcclll}&#10;p(x) = &{{ -0.25}}x^2&{{ +80}}x&{{ +0}}\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array}\qquad &#10;\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)&#10;\\\\\\&#10;\left( -\cfrac{80}{-0.50}~,~0-\cfrac{80^2}{-1} \right)\implies \left( \stackrel{\textit{quantity}}{160}~,~\stackrel{\textit{profit value}}{6400}  \right)

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\bf p(x)=-0.25x^2+70x\\\\&#10;-------------------------------\\\\&#10;\textit{ vertex of a vertical parabola, using coefficients}\\\\&#10;\begin{array}{lcclll}&#10;p(x) = &{{ -0.25}}x^2&{{ +70}}x&{{ +0}}\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array}\qquad &#10;\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)&#10;\\\\\\&#10;\left( -\cfrac{70}{-0.50}~,~0-\cfrac{70^2}{-1} \right)

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