Given:
Square DEFG = SIDE LENGTH = 2 UNITS
Square D'E'F'G' = SIDE LENGTH = 6 UNITS
The question was which scale factor was used to dilate square DEFG to square D'E'F'G'
From a side length of 2 units to a side length of 6 units
The scale factor used is 3.
2 * scale factor = 6
scale factor = 6/2
scale factor = 3
Answer:
The value of ∠A is 62° ⇒ c
The value of ∠B is 54°⇒ d
Step-by-step explanation:
<em>In a triangle, the measure of an exterior angle at a vertex of the triangle equals the sum of the measures of the two opposite interior angles to this vertex.</em>
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In Δ ABC
∵ The measure of the exterior angle at the vertex C = 116°
∵ The opposite interior angles to vertex C are ∠A and ∠B
∵ m∠A = (3x - 13)°
∵ m∠B = (2x + 4)°
→ By using the rule above
∴ (3x - 13) + (2x + 4) = 116
→ Add the like terms in the left side
∵ (3x + 2x) + (-13 + 4) = 116
∴ 5x + -9 = 116
∴ 5x - 9 = 116
→ Add 9 to both sides
∵ 5x - 9 + 9 = 116 + 9
∴ 5x = 125
→ Divide both sides by 5
∴ x = 25
→ To find the measures of angle A and B substitute x in their
measures by 25
∵ m∠A = 3(25) - 13 = 75 - 13
∴ m∠A = 62°
∴ The value of ∠A is 62°
∵ m∠B = 2(25) + 4 = 50 + 4
∴ m∠B = 54°
∴ The value of ∠B is 54°
Answer:
well, the answer sure is an answer!
Answer:
Truck can safely carry <em>2310 pounds </em> of cargo.
Step-by-step explanation:
Given the safety limit of weight to cross the bridge safely is 4 tons.
1 ton is equal to 2000 pounds.
so, 4 tons are equal to 2000 
4 = 8000 pounds
Now, given that
weight of empty truck and driver = 5690 pounds
To find:
Weight of cargo that the truck can safely carry ?
Solution:
Total weight of the truck is actually the combined weight of the empty truck, the drive and the cargo carried in it.
So, Total Weight allowed = 8000 pounds = 5690 pounds + Weight of Cargo
Weight of Cargo = 8000 - 5690 pounds
Weight of Cargo = <em>2310 pounds</em>
Truck can safely carry <em>2310 pounds </em> of cargo.
ANSWER
Explicit formula:
Recursive
EXPLANATION
The first term of the sequence is
The common difference is
The nth term is given by the formula,
The explicit formula is;
The recursive definition is
