The Bernoulli distribution is a distribution whose random variable can only take 0 or 1
- The value of E(x2) is p
- The value of V(x) is p(1 - p)
- The value of E(x79) is p
<h3>How to compute E(x2)</h3>
The distribution is given as:
p(0) = 1 - p
p(1) = p
The expected value of x2, E(x2) is calculated as:

So, we have:

Evaluate the exponents

Multiply

Add

Hence, the value of E(x2) is p
<h3>How to compute V(x)</h3>
This is calculated as:

Start by calculating E(x) using:

So, we have:


Recall that:

So, we have:

Factor out p

Hence, the value of V(x) is p(1 - p)
<h3>How to compute E(x79)</h3>
The expected value of x79, E(x79) is calculated as:

So, we have:

Evaluate the exponents

Multiply

Add

Hence, the value of E(x79) is p
Read more about probability distribution at:
brainly.com/question/15246027
Answer:
Answer Choice A
Step-by-step explanation:
I took this assignment
(please give brainliest)
1. The first 10 multiples of 13 are 13, 26, 39, 52, 65, 78, 91, 104, 117, and 130.
2. x - 5
3. x + 80
Answer:
Step-by-step explanation:
Answer:
1.thursday
his expenses was p26.85
2.monday he spent p40.8
3.18.90+23.15+11.80+16.35+9.20=approximately p55.6×30 days=p1,668
4.693.80-1,668
so he savings is completely enough