∑ ( from n = 1 to n =5 ) 3 · ( -2 ) ^( n -1 )
a 1 = 3 · ( -2 ) ^0 = 3
a 2 = 3 · ( - 2 ) = - 6
a 3 = 3 · 4 = 12
a 4 = 3 · ( - 8 ) = - 24
a 5 = 3 · 16 = 48
3 - 6 + 12 - 24 + 48 = 33
Answer: C ) 33
Answer:
Step-by-step explanation:
a: Wrong. The first thing that you have to notice is that the sum goes to infinity. If you want k=4 to be the last condition, then take out the 3 dots.
b: That's the answer.
c: wrong. You get a real mess when you let set k = 0. Try it on your calculator.
1 ÷ 0 = Watch carefully as your calculator mentally melts down.
d: wrong. It's just not right. The highest power is k^2. There is no way to get k^3
Answer: I think its 63−332+45−6
Step-by-step explanation:
Answer:
2nd option
Step-by-step explanation:
makes most sense
