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TiliK225 [7]
3 years ago
14

Answer correctly !!!!!!!!!! HELP ME PLEASE !!!!!!!!!!!!!!

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0
6.32455532 dipsh1t
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Please help asap<br><br> y= ?
Tanzania [10]

Answer:

y = 2|x| - 3

Step-by-step explanation:

We'll start with our parent function which is y = |x|. Notice that graph is translated down by 3 units. So, we'll add that:

y = |x| - 3

Also notice that the ordered pair (1, -1) is on the graph. |1| = 1, so a translation of -3 should take it to -2 and it should have been (1, -2). But, it's not so it must be that the graph is stretched/compressed. If you multiply every point by 2, it gives us the result we want. Say for example, f(1) = 2|1| - 3 = 2 - 3  = -1. We get the point (1, -1) which is exactly what we want. We write compressions as (where a is the compression/stretching constant):

y = a|x| + d

Our compression constant is 2, so our final answer is:

<em>y = 2|x| - 3</em>.

5 0
3 years ago
The Question
77julia77 [94]

Answer:

40

Step-by-step explanation:

Divide 12 by .40 (the percentage) to figure out what the full number would be.

5 0
3 years ago
Someone help pleeeeaSe
belka [17]

Answer:

The answer is D. 2x/15

5 0
3 years ago
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In the figure below X is best described as a
PolarNik [594]

Answer:

Idk

Step-by-step explanation:

Idk

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3 years ago
Please Answer The Question Below As Fast As Possible Who Answers First Get's Brainliest..
zheka24 [161]

Answer:

110

Step-by-step explanation:

Using the expansion

(a + b)³ = a³ + b³ + 3ab(a + b)

Given

x + \frac{1}{x} = 5 ( cube both sides )

(x + \frac{1}{x} )³ = 5³ = 125 ← expand left side using identity

x³ + \frac{1}{x^3} + 3(x × \frac{1}{x} )(x + \frac{1}{x} ) = 125

x³ + \frac{1}{x^3} + 3(1)(5) = 125

x³ + \frac{1}{x^3} + 15 = 125 ( subtract 15 from both sides )

x³ + \frac{1}{x^3} = 110

7 0
3 years ago
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