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2 years ago

What is the simplified form of the expression 3 + 8x − 2y − x + 1 + 4y

Mathematics

2 answers:

zloy xaker [14]2 years ago

6 0

7x +2y + 4

Hope that helped, Good luck! (:

Please mark Brainliest (:

Elodia [21]2 years ago

4 0

2y +7x+4

I think.....
Hope this helps please Press Thanks! <3

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10 points please answer correctly (due soon)

luda_lava [24]

The exponential equation of the model is A(t) = 2583 * 0.88^t and the multiplier means that the number of new cases in a week is 88% of the previous week

<h3>The function that models the data</h3>

The given parameters are:

New, A(t) = 2000

Rate, r = 12%

The function is represented as:

A(t) = A * (1 - r)^t

So, we have:

2000 = A * (1 - 12%)^t

This gives

2000 = A * (0.88)^t

2 weeks ago implies that;

t = 2

So, we have:

2000 = A * 0.88^2

Evaluate

2000 = A * 0.7744

Divide by 0.7744

A = 2583

Substitute A = 2583 in A(t) = A * 0.88^t

A(t) = 2583 * 0.88^t

Hence, the exponential equation of the model is A(t) = 2583 * 0.88^t

<h3>The interpretation of the multiplier</h3>

In this case, the multiplier is 88% or 0.88

This means that the number of new cases in a week is 88% of the previous week

Read more about exponential equation at

brainly.com/question/2456547

#SPJ1

8 0

1 year ago

Kendra’s xylophone is in the shape of the trapezoid shaken at the right. Describe any parallel,perpendicular, or congruent sides

Nookie1986 [14]

The left and right sides make up the parallel sides of the trapezoid. The top and bottom would be congruent but not parallel.

6 0

2 years ago

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$