The polynomial equation x3+x2=-9x-9 has complex roots +-3i . What is the other root? Use a graphing calculator and a system of e
2 answers:
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Answer:
- <em>convert </em>the mixed fractions to improper fractions (where the numerator is greater than or equal to the denominator): multiply the whole number part by the fraction's denominator, add that to the numerator, write the result on top of the denominator.
- if the denominators are not the same, work out the common denominator and <em>rewrite </em>the fractions with the same denominators
- subtract by subtracting the numerators and writing the result over the denominator
- convert back to mixed fractions by dividing the numerator by the denominator, write down the whole number answer, write down the remainder above the denominator.
Example
convert to improper fractions:
common denominator = 3 × 5 = 15, so:
subtract:
convert back to mixed fractions:
Answer:
(g-f) (-1)= sqrt(15)
(f/g)(-1)= 0
(g+f)(2)=sqrt(3)-3
(g*f)(2)=-3*sqrt(3)
Step-by-step explanation:
We have to eval the expressions given in the point indicated.
Lets start by the first equation
(g-f)(-1)= g(-1) - f(-1)= =
Now, lest continue with the others
(f/g)(-1)= f(-1)/g(-1)= (1-1)/sqrt(15)=0
(g+f)(2)=g(2)+f(2)=sqrt(3)-3
(g*f)(2)=g(2)*f(2)=sqrt(3)*(-3)=-3sqrt(3)