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2 years ago

Write the equation of the line fully simplified slope-intercept form

Mathematics

2 answers:

Nadusha1986 [10]2 years ago

8 0

Answer:

y = (5/2)x - 5

Step-by-step explanation:

SLOPE:

The slope is rise over run, and in this case (thanks to the graph), we can do the [difference of y] / [difference of x] pretty easily. This is 5 / 2

Y-INTERCEPT:

Y-intercept is simple: where the line touches the y-axis. This happens at y = -5.

Therefore, the equation y = (5/2)x - 5

saul85 [17]2 years ago

7 0

Answer:

y=mx+b

Step-by-step explanation:

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PLEASE HELP!!! OFFERING 50 POINTS!!!!

Otrada [13]

Answer:

slope-intercept form y= -2/3 x + 490 slope is -2/3 y intercept is (0.490)

Step-by-step explanation:

2x+3y= 1470

3y= 1470-2x

y= 1470/3- 2/3 x

y= -2/3 x+ 490

slope is -2/3 and y intercept is 490 when x =0

the graph represent the amount of sandwiches that Sal's shop sold, where x is the number of sandwiches and y is the number of wraps sold. so that x won't exceed 735 sandwiches : 0≤x≤735 and 0≤ y≤490.

<u>total profit is 1593.</u>

2x+3y= 1593

y= -2/3 x + 531

similar : the two functions have the same slope -2/3

difference: 0≤ y≤531

0≤x≤796.5

the two line are parallel

7 0

2 years ago

What is 4 1/4 divied by 3 1/2

Ludmilka [50]

Answer:

1 3/14

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$