All categories

2 years ago

SOMEONE HELP!! ASAP I will give brainliest ! Please and ty !!

Mathematics

1 answer:

Kobotan [32]2 years ago

3 0

4.24

Step by step explanation:

You might be interested in

What is the equation of the line that contains the point (-1, 4) and has a slope of 3?

sertanlavr [38]

Let's write the equation with formula:-

$\boxed{ \sf \: formula : y -y_{1} = m(x - x_{1})}$

Where,

x1 is -1 and y1 is 4 and m is 3

$\tt \: y - 4= 3(x - ( - 1))$

$\tt \: y - 4 = 3(x + 1)$

$\tt \: y - 4 = 3x + 3$

$\tt \: y = 3x + 3 + 4$

$\tt \: y = 3x + 7$

<em>Thus, The correct choice is option C!!~</em>

4 0

2 years ago

Read 2 more answers

An airplane on autopilot took 8 hours to travel 5,744 kilometers. What is the unit rate for kilometers per hour?

guajiro [1.7K]

Answer:718 kilometers per hour

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Matt has two very active dogs...

olga55 [171]

I can’t help u with very little info

6 0

3 years ago

Read 2 more answers

Which of the following sets are closed under subtraction? Select all that apply.

Vanyuwa [196]

only integers and polynomials are under subtraction.

7 0

3 years ago

Read 2 more answers

Circle O has a center at (-2, 10) and a

allsm [11]

Answer:

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

$distance = \sqrt{(y1 - y2)^{2} + {(x1 - x2)}^{2} }$

A. Distance between 2 points

$= \sqrt{ {(10 + 5)}^{2} + ( - 2 + 6)^{2} } \\ = \sqrt{15 ^{2} + {4}^{2}} \\ = \sqrt{241} \\ = 15.524 \: units$

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2} } \\ = \sqrt{ {6}^{2} } \\ = 6 \: units$

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + {( - 2 - 6)}^{2} } \\ = \sqrt{ {6}^{2} + ( - 8)^{2} } \\ = \sqrt{100} \\ = 10 \: units$

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

$= \sqrt{ {(10 - 8)}^{2} + {( - 2 - 8)}^{2} } \\ = \sqrt{2^{2} + ( - 10)^{2} } \\ = \sqrt{104} \\ = 10.198 \: units$

(to 5 s.f.)

Point D also lies outside Circle O.

8 0

3 years ago