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Nonamiya [84]
3 years ago
13

Point P’(5,-4) is the image of point(2,3) under a translation what is the image of 6,-2 under the same translation

Mathematics
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer:

C

Step-by-step explanation:

(2,3) to (5,-4) its (3,-7) so you jus add (3,-7) to (6,-2) and it gives you (9,-9)

I dont know if it makes sense but yea

You might be interested in
Divide.
algol13

Answer:

Answer in simplified form is - 10 1/2 .

Step-by-step explanation:

We have given,

(5 1/4) ÷ (- 2 1/2)

This can be simplified as :

(5 1/4) ÷ ( -2 1/2)

Since 5 1/4 = 21/4  and -2 1/ 2 = -5/2

So we can write,

(5 1/4) ÷ ( -2 1/2) = 21/4 ÷ ( - 5/2)

or (21/4) / (-5/2)

or ( 21/4) * (-2/5)

or -42/20

or -21/10

or - 10 1/2 , this is the answer

Hence we get answer in simplified form as -10 1/2

7 0
3 years ago
Use the x-intercept method to find all real solutions of the equation.x3-10x2=27x-18=0
g100num [7]

x^3-10x^2=27x-18=0 has no solutions

x^3-10x^2-27x-18=0 has 3 solutions

x^3-10x^2-27x-18=0 also has three solutions


3 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
There are 480 sophomores and 520 juniors in a high school. Find the ratio of juniors to sophomores
kow [346]

Answer:

13:12, 13 to 12, or 13/12

Step-by-step explanation:

520:480

Divide both numbers by GCF (40)

13:12

4 0
3 years ago
Hello can you please help me posted picture of question
allsm [11]
Total number of seats = 5
Total number of friends = 5

We want to find in how many ways the 5 friends can sit or be arranged in 5 seats. This can be found using permutations.So we are to find the permutations of 5 objects taken 5 at a time. This can be expressed as 5P5.

5P5 = 120

So, the 5 friends can sit in 120 different ways.

The correct answer is option D
4 0
4 years ago
Read 2 more answers
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