We have that
x²<span>-8x=39
</span>
<span>Group terms that contain the same variable</span>
(x²-8x)=39
Complete
the square. Remember to balance the equation by adding the same constants
to each side
(x²-8x+16)=39+16
Rewrite as perfect squares
(x-4)²=55-------> (x-4)²-55=0
(+/-)]x-4]=√55
(+)]x-4]=√55--------> x=4+√55
(-)]x-4]=√55-------> x=4-√55
the answer is
(x-4)²-55=0
Answer:
a. reflection over y axis, then reflection over x-axis
b. xy=qh, xz=qj, yz=jh
c.Both triangles are congruent because all of the sides are congruent
Step-by-step explanation:
Answer:
I dont know what the answer is exactly
Answer:
68
Step-by-step explanation:
The expression is given as:
4( 3+ 7y) + 6(2 - y)
It is known that y is equal to 2. Therefore, substitute 2 in for y.
4(3+7(2))+6(2-2)
Now, solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction
Solve inside of the parentheses first.
4(3+7(2))+6(2-2)
4(3+14)+6(0)
4(17)+6(0)
Multiply
68+0
Add
68
