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stich3 [128]
2 years ago
8

Help pls!! 8 1/2 miles in 1/2 hour

Mathematics
1 answer:
katrin2010 [14]2 years ago
8 0

3 minutes per mile.

or

17mph

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ada writes 10 + 8 = 18 on the board . to use the commutative property of addition to rewrite ada's addition sentence. what numbe
Mashcka [7]
8+10 = 18 is what it is I'm pretty sure
6 0
3 years ago
A skateboard was reduced in price from $50 to 43 what was the percent decrease
hammer [34]

Answer:

14%

Step-by-step explanation:

If you subtract 50-14% you get 43.

7 0
3 years ago
A circle has an area of 200.96 units2 and a circumference of 50.24 units. If the radius is 8 units, what can be said about the r
AleksandrR [38]

Answer:

C. The ratio of the area to the circumference is equal to half the radius.

Step-by-step explanation:

The area of a circle can be written as;

Area A = πr^2

The circumference of a circle is;

Circumference C = 2πr

Using the formula, w can derive the relationship between the two variables.

A = kC

k = A/C

Substituting the two formulas;

k = (πr^2)/(2πr) = r/2

So,

A = (r/2)C

A/C = r/2

The ratio of the area to the circumference is equal to half the radius.

Given;

Area = 200.96

Circumference = 50.24

Radius = 8

To confirm;

k = r/2 = 8/2 = 4

Also,

A/C = 200.96/50.24

A/C = 4

6 0
3 years ago
Let x=number of cds and y=number of dvds
Elis [28]
X + y = 40.....multiply by -4
4x + 6y = 180
-------------------
-4x - 4y = -160 (result of multiplying by -4)
4x + 6y = 180
------------------add
2y = 20
y = 20/2
y = 10 <===

x = 30

6 0
3 years ago
A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates
son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector =\frac{\theta}{360}X\pi R^2

Area of the smaller sector =\frac{\theta}{360}X\pi r^2

Area of shaded part =Area of the larger sector-Area of the smaller sector

=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)

From the diagram, R=10 Inch, r=10-7=3 Inch, \theta=95^\circ

Therefore, Area of the sector cleaned

=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches

7 0
3 years ago
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