We have,
(2y)^3 × y^-1
Simplify the term (2y)^3
= 8y^3 × y^-1
Now, multiply the terms with the same base y by adding their exponents.
Note: Using exponent product rule x^y × x^z = x^(y+z)
= 8y^{3+(-1)}
= 8y^(3-1)
= 8y^(3-1)
= 8y^2
Answer:
Step-by-step explanation:
49
Let's solve your inequality step-by-step.
<span><span><span><span><span>3y</span>−1</span>+<span>2y</span></span>+3</span>>5
</span>Step 1: Simplify both sides of the inequality.<span><span><span>5y</span>+2</span>>5
</span>Step 2: Subtract 2 from both sides.<span><span><span><span>
5y</span>+2</span>−2</span>><span>5−2</span></span><span><span>
5y</span>>3</span>
Step 3: Divide both sides by 5.<span><span><span>
5y/</span>5</span>><span>3/5</span></span><span>
y><span>3/<span>5
hopefully this helps and here's a link that i used to use a lot in middle school
https://www.symbolab.com/solver/solve-for-equation-calculator
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Answer:
y = 0.5x + 1
Step-by-step explanation:
