We can use the distance formula to find the distance between these points.
Distance formula: 
√(-5 - 6)² + (-3 - (-3))²
√121 = 11
The difference between the points is 11.
6/8 *3/2.
6*3=18. /8*2=16
18/16
Divide top and bottom by 2
9/8
Answer: The critical value for a two-tailed t-test = 2.056
The critical value for a one-tailed t-test = 1.706
Step-by-step explanation:
Given : Degree of freedom : df= 26
Significance level : 
Using student's t distribution table , the critical value for a two-tailed t-test will be :-

The critical value for a two-tailed t-test = 2.056
Again, Using student's t distribution table , the critical value for a one-tailed t-test will be :-

The critical value for a one-tailed t-test = 1.706
Answer:
the probability of no defects in 10 feet of steel = 0.1353
Step-by-step explanation:
GIven that:
A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.
Let consider β to be the average value for defecting
So;
β = 2
Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.
Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2
i.e

the probability mass function can be represented as follows:

where;
y = 0,1,2,3 ...
Hence, the probability of no defects in 10 feet of steel
y = 0


P(y =0) = 0.1353
Answer:
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