Question

Debbie launched a toy rocket off a hill next to Lake Lakewood. The height h of the rocket in feet above the surface of the lake can be modeled by h = 340 + 100 t − 16 t 2 h=340+100t−16t 2 , where t is the time in seconds after the launch

Answer 1

Answer:

t = 8.69 s

Step-by-step explanation:

The height h of the rocket in feet above the surface of the lake can be modeled by :

$h=340+100t-16t^2$

Let we need to find the time to reach the ground. When it reach the ground, h = 0

$340+100t-16t^2=0$

We need to find the value of t.

t = 8.69 s and -2.45 s

Neglecting negative value,

t = 8.69 s

Hence, it will take 8.69 s to reach the ground.