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-BARSIC- [3]
2 years ago
10

Q1. The speed limit on a road is 40km/h. A scooter drives 9

Mathematics
1 answer:
Drupady [299]2 years ago
7 0
No because if you multiply 15 by 4, that is equal to 60 min= an hour. so you have to multiply the 9 so you’re in terms of hours. so he is going 36
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there are 400 students and 4/5 have purchased tickets there needs to be 2 chaperones for every 75 students how many chaperones a
Vesna [10]

Answer:

5 chaperones are needed.

Step-by-step explanation:

400 x 4/5 = 320

320 ÷ 75 = 4.3

3 0
3 years ago
The students in Mr. Wilson's Physics class are making golf ball catapults. The
Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is 0 \leq x \leq 48.6\ ft and the range is 0 \leq y \leq 8.3\ ft

Step-by-step explanation:

we have

y=-0.014x^{2} +0.68x

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's  distance from the catapult in feet

y is the flight of the balls in feet

Part a)  How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-0.014x^{2} +0.68x=0

so

a=-0.014\\b=0.68\\c=0

substitute in the formula

x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}

x=\frac{-0.68(+/-)0.68} {(-0.028)}

x=\frac{-0.68(+)0.68} {(-0.028)}=0

x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

y=-0.014x^{2} +0.68x

Find out the derivative and equate to zero

0=-0.028x +0.68

Solve for x

0.028x=0.68

x=24.3

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint  between the x-intercepts

x=(0+48.6)/2=24.3\ ft

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

y=-0.014(24.3)^{2} +0.68(24.3)

y=8.3\ ft

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A  reasonable domain is the distance between the two x-intercepts

so

0 \leq x \leq 48.6\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A  reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

0 \leq y \leq 8.3\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0
2 years ago
A tree casts a shadow that is 231 cm long. Janet is 170 cm tall and she casts a shadow that is 102 cm long. How tall is the tree
Mekhanik [1.2K]

Answer:

139 cm

Step-by-step explanation:

7 0
2 years ago
Whats 2.42 as a fraction?
Debora [2.8K]
2 42/100 turn it to a fraction
8 0
3 years ago
PLEASE HELP PLEASE PLEASE
sp2606 [1]

Answer:

14.8

Step-by-step explanation:

By the Pythagorean theorem, ...

... x² = 7² + 13² = 218

... x = √218 ≈ 14.7648 ≈ 14.8

4 0
3 years ago
Read 2 more answers
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