3x - 1 = 9x + 2
3x (-3x) - 1 (-2) = 9x (-3x) + 2 (-2)
-3 = 6x
-3/6 = 6x/6
-1/2 = x
hope thsi helps
Answer:
for this you should use photomath all you do is take a picture of each problem and put the answer down
So you have x^3 - 4x = 0. What you can do is pull out an x from both x^3 and - 4x so it looks like this:

Then you can find a number that makes the part inside the parentheses turn into zero. For beginners, it may be easier to write it out seperately and solve for x.

We need to solve for x, so the first step is to add 4 to both sides, so we get something like this:

Then, we can square root both sides to get rid of the power on the x, so it looks like this:

Now, every square root has two answers, a positive and a negative. If we look at the bottom example:


We can see that both -2 and 2 to the power of two will equal to 4.
So finally, we get:

These are the other 'Zero's for the original function. If you are not sure of what a 'Zero' is, it is where the function crosses over the x-axis on a graph.
Answer:
53
Step-by-step explanation:
To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.