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e-lub [12.9K]
2 years ago
6

X - 4y = 28 x+2y = -2 it’s substitution

Mathematics
1 answer:
Luda [366]2 years ago
6 0

Step-by-step explanation:

hope this will help you!!!.. plz follow me!!

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Solve for x 3x-1=9x+2
ANEK [815]
3x - 1 = 9x + 2

3x (-3x) - 1 (-2) = 9x (-3x) + 2 (-2)

-3 = 6x

-3/6 = 6x/6

-1/2 = x

hope thsi helps
4 0
3 years ago
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MAVERICK [17]

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3 years ago
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One zero of x^3 - 4x = 0 is 0 what are the other zeros of the function
myrzilka [38]
So you have x^3 - 4x = 0. What you can do is pull out an x from both x^3 and - 4x so it looks like this:

x( {x}^{2} - 4) = 0

Then you can find a number that makes the part inside the parentheses turn into zero. For beginners, it may be easier to write it out seperately and solve for x.

{x}^{2} - 4 = 0

We need to solve for x, so the first step is to add 4 to both sides, so we get something like this:

{x}^{2} = 4

Then, we can square root both sides to get rid of the power on the x, so it looks like this:

x = \sqrt{4}

Now, every square root has two answers, a positive and a negative. If we look at the bottom example:

{2}^{2} = 4

{( - 2)}^{2} = 4

We can see that both -2 and 2 to the power of two will equal to 4.

So finally, we get:

x = - 2 \: and \: 2

These are the other 'Zero's for the original function. If you are not sure of what a 'Zero' is, it is where the function crosses over the x-axis on a graph.
5 0
2 years ago
In the data set below, what is the interquartile range?
satela [25.4K]

Answer:

53

Step-by-step explanation:

To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

3 0
2 years ago
Help me with this ASAP PLEASE
xxMikexx [17]
It is the first one
5 0
3 years ago
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