All categories

3 years ago

Which of the quadratic functions has the widest graph? y = 0.3x2 y = –4x2

Mathematics

2 answers:

Shkiper50 [21]3 years ago

8 0

Yes, Y = 0.3x^2 is correct!!

Alenkinab [10]3 years ago

4 0

A vertical stretching is the stretching of the graph away from the x-axis.
A vertical compression is the squeezing of the graph towards the x-axis.
A compression is a stretch by a factor less than 1.

For the parent function y = f(x), the vertical stretching or compression of the function is a f(x).

If | a | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of a units.
If | a | > 1, then the graph is stretched vertically by a factor of a units.

For values of a that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.

Thus, the equation with the widest graph is 0.3x^2.

You might be interested in

Use a quadratic equation to find two numbers whose sum is 5 and whose product is - 24.

prisoha [69]

Hello
if m s : sum and p : product
the quadratic equation is : x²-sx+p=0
s = 5 p=-24
x²-5x-24 = 0

8 0

4 years ago

What direction will this object accelerate? Please give me an explanation as well I will be marking brainiest (NO LINKS)

gavmur [86]

Answer:

It will be stationary because there is an equal amount of force from each direction.

Step-by-step explanation:

6 0

3 years ago

PLS HELP I WILL MARK BRAINLIEST

Anestetic [448]

Answer:

16 degrees

Step-by-step explanation:

Divide ABD by 4 to produce a 1:3 ratio of the angles

6 0

3 years ago

An architect believes that kitchens should be 2.25 times as long as they are wide. Set up a proportion and solve it to find how

White raven [17]

Answer:

2.71 feet

Step-by-step explanation:

An architect believes that kitchens should be 2.25 times as long as they are wide.

This means

Width of kitchen = 2.25 × Length of the Kitchen

W = 2.25L

L = W/2.25

We are asked: how long a kitchen should be if it is 6.1 feet wide.

We have the proportion

L = W/2.25

W = 6.1

L = 6.1/2.25

L = 2.7111111111 feet

Therefore, the length of a kitchen = 2.71 feet when the kitchen is 6.1 feet wide.

3 0

3 years ago

Use the fundamental counting principle. The students in the 14-member advanced communications design class at Center City Commu

vlabodo [156]

Answer:

Team can be formed in 40040 different ways.

Step-by-step explanation:

This is a question where three important concepts are involved: permutations, combinations and the fundamental counting principle or multiplication principle.

One of the most important details in the problem is when it indicates that "[...]The team must have a team leader and a main presenter" and that "the other 3 members have no particularly defined roles".

This is a key factor to solve this problem because it is important the order for two (2) positions (team leader and main presenter), but no at all for the rest three (3) other positions.

By the way, notice that it is also important to take into account that no repetition of a team member is permitted to form the different teams requested in this kind of problem: once a member have been selected, no other team will have this member again.

The fundamental counting principle plays an interesting role here since different choices resulted from those teams will be multiplied by each other, and the result finally obtained.

We can start calculating the first part of the answer as follows:

First Part

How many teams of 2 members (team leader and main presenter) can be formed from 14 students? Here the order in which these teams are formed is crucial. There will be a team leader and a main presenter, no more, formed from 14 students.

This part of the problem can be calculated using permutations:

$\frac{n!}{(n-k)!}$ or $\frac{14!}{(14-2!)}= \frac{14*13*12!}{12!}$ .

Since $\frac{12!}{12!}=1$ , then the answer is $14*13$ .

In other words, there are 14 choices to form a team leader (or a main presenter), and then, there are 13 choices to form the main presenter (or a team leader), and finally there are 14*13 ways to form a 2-member team with a leader and a main presenter from the 14 students available.

Second Part

As can be seen, from the total 14 members, 2 members are out for the next calculation (we have, instead, 12 students). Then, the next question follows: How many 3-member teams could be formed from the rest of the 12 members?

Notice that order here is meaningless, since three members are formed without any denomination, so it would be the same case as when dealing with poker hands: no matter the order of the cards in a hand of them. For example, a hand of two cards in poker would be the same when you get an ace of spades and an ace of hearts or an ace of hearts and an ace of spades.

This part of the problem can be calculated using combinations:

$\frac{n!}{(n-k)!k!}$ or $\frac{12!}{(12-3)!*3!}= \frac{12*11*10*9!}{(9!*3!)}$ .

Since $\frac{9!}{9!}=1$ , then the anwer is $\frac{12*11*10}{3*2*1} = \frac{12}{3}*\frac{10}{2}*11=4*5*11$ .

Final Result

Using the multiplication principle, the last thing to do is multiply both previous results:

How many different ways can the requested team be formed?

14*13*4*5*11 = 40040 ways.

Because of the multiplication principle, the same result will be obtained if we instead start calculating how many 3-member teams could be formed from 14 members (combinations) and then calculating how many 2-member team (team leader and main presenter) could be formed from the rest of the 11 team members (permutations).

5 0

3 years ago