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gogolik [260]
2 years ago
6

Stephen won tickets playing the pool game at the local arcade. The first time, he won 90 tickets. The second time, he won a bonu

s, which was 5 times the number of tickets of the original second prize. Altogether he won 300 tickets. How many tickets was the original second prize?
Mathematics
1 answer:
EastWind [94]2 years ago
8 0

Answer:

42 tickets

Step-by-step explanation:

First winning = 90 tickets

Bonus won = 5 times the number of tickets of the original second prize

Total tickets won = 300

That is ;

First winning + bonus = 300 tickets

Let :

Number Tickets won by original second price = x

Bonus = 5x

Then;

90 + 5x = 300

5x = 300 - 90

5x = 210

x = 210 / 5

x = 42

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