m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
Answer:
Step-by-step explanation:
we are given a exponential function
where x represents the number and f(x) represents the amount
we are also given that when x is 3 then f(x) is 59 likewise when x is 6 then f(x) is 2165
to figure out the average rate of change between 3 and 6 we can consider the average rate of change formula given by
substitute what we have:
simplify substitution:
simplify division:
hence, the average rate of change between 3 and 6 is <u>7</u><u>0</u><u>2</u>
The two inequalities formed will be:
One for ticket quantity:
x + y ≤ 600
One for funds generated via tickets:
5x + 7y ≥ 3500
Equating x to 330,
5(330) +7y ≥ 3500
y = 265
Checking if the other inequality holds true:
330 + 265 ≤ 600
595 ≤ 600
This inequality is still true so they can sell 265 tickets on the event day and cover their expenses.
25% = 0.25
70*0.25 = 17.50
Subtract 17.50 from 70
70-17.50 = $52.50
Answer:
the answer is c
Step-by-step explanation:
