The answer is 9000 millimeters because every meter is 1000 millimeters.
Answer:
r is always between 0 and 1
Step-by-step explanation:
The untrue statement is ...
r is always between 0 and 1
One way you can tell is that it is inconsistent with the true statement |r| ≤ 1.
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<em>Comment on correlation coefficient</em>
The correlation coefficient (r) is the ratio of the covariance of x and y to the product of the standard deviations of x and y. This formula is symmetrical in x and y, so it doesn't matter which data set you call x and which one you call y. Similarly, the units cancel, so r is a unitless number, and the units of x and y don't matter, either.
Answer:
R3 <= 0.083
Step-by-step explanation:
f(x)=xlnx,
The derivatives are as follows:
f'(x)=1+lnx,
f"(x)=1/x,
f"'(x)=-1/x²
f^(4)(x)=2/x³
Simialrly;
f(1) = 0,
f'(1) = 1,
f"(1) = 1,
f"'(1) = -1,
f^(4)(1) = 2
As such;
T1 = f(1) + f'(1)(x-1)
T1 = 0+1(x-1)
T1 = x - 1
T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2
T2 = 0+1(x-1)+1(x-1)^2
T2 = x-1+(x²-2x+1)/2
T2 = x²/2 - 1/2
T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3
T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3
T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)
Thus, T1(2) = 2 - 1
T1(2) = 1
T2 (2) = 2²/2 - 1/2
T2 (2) = 3/2
T2 (2) = 1.5
T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)
T3(2) = 4/3
T3(2) = 1.333
Since;
f(2) = 2 × ln(2)
f(2) = 2×0.693147 =
f(2) = 1.386294
Since;
f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).
Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,
Since;
f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2
Finally;
R3 <= |2/(4!)(2-1)^4|
R3 <= | 2 / 24× 1 |
R3 <= 1/12
R3 <= 0.083
The equation factored would be (x+7)(x-2). As 7-2=5 and (7)(2)=14.
The arc length of the circle is 5π/9 units
<h3>How to determine the arc length?</h3>
From the question, we have the following parameters
Angle, ∅ = 5π/9
Radius, r = 1 unit
The arc length (x) is calculated as
x = r∅
Substitute the known values in the above equation
x = 5π/9 * 1
Evaluate the product
x = 5π/9
Hence, the arc length of the circle is 5π/9 units
Read more about arc lengths at:
brainly.com/question/2005046
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