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2 years ago

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The sum of the measures of angle A and angle B is 180 degrees. The measure of angle A is (4x + 12) The measure of angle B is 60

degrees What is the value of x?

1 answer:

BARSIC [14]2 years ago

5 0

Answer:

Rolf prepares four solutions using different solutes as shown in the table be❤️low.

Which solution is unsaturated?

Solution A

Solution B

Solution C

Solution D

Step-by-step explanation:

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Indicate the equation of the given line in standard form. The line that is the perpendicular bisector of the segment whose endpo

noname [10]

Well the line that bisects RS, will cut RS in two equal halves, therefore, that line will cut RS perpendicularly at the midpoint of RS.

now, what the dickens is the midpoint of RS anyway?

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
R&({{ -1}}\quad ,&{{ 6}})\quad 
% (c,d)
S&({{ 5}}\quad ,&{{ 5}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{5-1}{2}~~,~~\cfrac{5+6}{2} \right)\implies \stackrel{midpoint}{\left(2~~,~~\frac{11}{2} \right)}$

so, we know that perpendicular line, will have to go through (2, 11/2)

now, a perpendicular line to RS, will have a negative reciprocal slope to it. Well, what is the slope of RS anyway?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -1}}\quad ,&{{ 6}})\quad 
% (c,d)
&({{ 5}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-6}{5-(-1)}\implies \cfrac{5-6}{5+1}\implies -\cfrac{1}{6}$

and let's check the reciprocal negative of that,

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{6}\\\\
slope=-\cfrac{1}{{{ 6}}}\qquad negative\implies +\cfrac{1}{{{ 6}}}\qquad reciprocal\implies + \cfrac{{{ 6}}}{1}\implies 6$

so, then, what's is the equation of a line whose slope is 6, and goes through 2, 11/2?

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 2}}\quad ,&{{ \frac{11}{2}}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\cfrac{11}{2}=6(x-2)
\\\\\\
y-\cfrac{11}{2}=6x-12\implies -6x+y=-12+\cfrac{11}{2}\implies \stackrel{\textit{standard form}}{-6x+y=-\cfrac{13}{2}}$

6 0

2 years ago

Really need the answers pleases I will be forever thankful it’s over parallels lines and transversals I’m in 8th grade.

xxMikexx [17]

Where are the questions lol

3 0

3 years ago

Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> ._.

ra1l [238]

There are 40 black and 20 blue so if you divide by 20 the ratio is 2:1

8 0

3 years ago

Read 2 more answers

Dr. W Sweet Rides Car Rental charges a flat fee of $24 and an additional $0.35 for every mile the car is driven. Which function

kompoz [17]

Step-by-step explanation:

this is a strange rental company charging no daily fees.

but ok.

so, we have a fixed part of the cost : $24

we have to pay that no matter how many miles we drive. even for 0 miles, just to get the keys to the car.

and then we pay $0.35 for every mile driven.

that makes our function

C(x) = 0.35x + 24

and if we drive 40 miles, that makes x = 40.

C(24) = 0.35×40 + 24 = 14 + 24 = $38

it would cost us $38.

3 0

2 years ago

choli [55]

Hello from MrBillDoesMath!

Answer:

x = 0, 7

Discussion:

f(g(x)) =

f ( x^2-7x) =

1/ ( x^2 - 7x)

The points NOT in the domain are those where the denominator, x^2 - 7x = 0.

x^2 - 7x = 0 => factor x from each term

x(x-7) = 0 => one or both terms must each 0

x = 0 or x =7

Thank you,

MrB

6 0

3 years ago