We can write and solve the differential equation that fits the statement given;
dy/dt = k(50-t)
∫dy = ∫ k(50-t)dt
= ∫ (50k - kt) dt
therefore;
y = 50kt - k/2(t²) + C
Alternatively, can be written as
y = - k/2 (50-t)² + C)
5.392 is 5.39 rounded to the nearest hundredth
X+(x+2)+(x+4)=396, x+x+x+6=396, 3x+6=396, 3x=396-6, 3x=390, x=130, x+2=130+2=132, x+4=130+4=134. The three consecutive even integers are 130, 132, 134
Hello! So the sweater was marked off by 20% and the sale price is $60. To find the original price of the sweater, we can write and solve a proportion. Set it up like this:
60/x = 80/100
This is because 60 is a part of the whole (the original price), and even though the price was marked down by 20%, you still pay 80% of that price. Let's cross multiply the values. 60 * 100 is 6,000. 80 * x is 80x. That makes 6,000 = 80x. Now, divide each side by 80 to isolate the x. 80x/80 cancels out. 6,000/80 is 75. Let's check this. 75 * 80% (0.8) is 60. There. x = 75. The regular price of the sweater is $75.
CubeSA=6 squares
SA=6s^2
SA=24
24=6s^2
divide 6
4=s^2
2=s
quadrupled means times 4
2*4=8
8=new side
sub back
SA=6(8^2)
SA=6(64)
new SA=384 cm^2
