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2 years ago

Two particles are projected simultaneously towards each other from opposite ends of a straight

Mathematics

1 answer:

Anit [1.1K]2 years ago

8 0

Answer:

The problem with this question is that it is missing an important number, which is the length of the tube. Assuming that the tube is 10 meters long (=1,000 centimeters long)

time (in distance traveled distance traveled distance

seconds) by particle A in cms by particle B in cms between both

particles in cms

1 97 49 854

2 93 47 714

3 89 45 580

4 85 43 452

5 81 41 330

6 77 39 214

7 73 37 104

8 69 35 0

After 8 seconds both particles should meet. Particle A traveled 664 centimeters and particle B traveled 336 centimeters.

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Sarah is 25 years older than her son gavin in 10 years sarah will be twice gavin's age how old was sarah and gavin now

Alla [95]

Sarah is 40 and gavin is 15

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2 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

Ede4ka [16]

Answer:

5 percent per annum

Step-by-step explanation:

interest rate:

interest: $1800

principal: $18000

duration: 2 years

1800/ 18000 * 100

result is 10%

Since interest is 10% in 2 years, 10% / 2

interest is 5% per year.

8 0

2 years ago

Helpppp!!!! ASAP !!!!!!!!!!! Nowwwwwww hellpppp!!!

FromTheMoon [43]

1. The fractions shown are 3/4 and 6/8.
2. The multiplier is 2.
3. The fractions shown are 12/18 and 4/6
4. The divisor is 3.

7 0

2 years ago

Directed line segment has endpoints P(– 8, – 4) and Q(4, 12). Determine the point that partitions the directed line segment in a

larisa86 [58]

Answer:

Point (1,8)

Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

$[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]$

Let us substitute coordinates of point P and Q as:

$x_1=-8$ ,

$y_1=-4$

$x_2=4$

$y_2=12$

$m=3$

$n=1$

$[x=\frac{(3*4)+(1*-8)}{3+1},y=\frac{(3*12)+(1*-4)}{3+1}]$

$[x=\frac{12-8}{4},y=\frac{36-4}{4}]$

$[x=\frac{4}{4},y=\frac{32}{4}]$

$[x=1,y=8]$

Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.

7 0

2 years ago