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Annette [7]
3 years ago
14

Jamal wants to draw a right triangle and label it JKL​

Mathematics
2 answers:
defon3 years ago
7 0
The answer is B: (-4,-2)
Cerrena [4.2K]3 years ago
7 0

Answer:

Calm down jamal don't go pulling out the nine

Step-by-step explanation:

this is just a joke

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El prestigioso hotel Los Cisnes, cobra la recepción a las delegaciones extranjeras de acuerdo con la siguiente política: Las del
dem82 [27]

Answer:

"x" cantidad de personas, que será igual a

f(x) = $10x   Si   x < 30

f(x) = $9.5x si x ≥ 30

Si tenemos que son 29 personas entonces el costo es de:

f(x) = $10*29 = $290

Si incluye un miembro adicional

f(x) = $9.5*30 = $285

Ahorra un total de: $290 - $285 = $5

8 0
3 years ago
(xsinA-ucosA)^2+(xcosA+ysinA)^2=x^2+y^2​
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Answer:

u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)

Step-by-step explanation:

Solve for u:

(x sin(A) - u cos(A))^2 + (x cos(A) + y sin(A))^2 = x^2 + y^2

Subtract (x cos(A) + y sin(A))^2 from both sides:

(x sin(A) - u cos(A))^2 = x^2 + y^2 - (x cos(A) + y sin(A))^2

Take the square root of both sides:

x sin(A) - u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Subtract x sin(A) from both sides:

-u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) - x sin(A) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Divide both sides by -cos(A):

u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Subtract x sin(A) from both sides:

u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or -u cos(A) = -x sin(A) - sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)

Divide both sides by -cos(A):

Answer:  u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)

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3 years ago
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hope this helps

this means that nothing is growing or decreasing
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3 years ago
Plz help I need help I don't under stand help on the hole page plzz
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