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Tcecarenko [31]
3 years ago
7

What is formed at a divergent plate boundary?

Chemistry
1 answer:
masya89 [10]3 years ago
3 0

Answer:

Mountains or oceanic crust

Explanation:

Most divergent plate boundaries are underwater and form submarine mountain ranges called oceanic spreading ridges.

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PLEASE HELP ASAP
Inessa05 [86]

The enthalpy change for the reaction 2K + S + K2S using the following thermochemical reactions is mathematically given as

dn=70.7kg

<h3>What is the enthalpy change for the reaction?</h3>

Generally, the equation for the  Chemical reaction is mathematically given as

2k+s----->K2S

Therefore

KS+K----->K2S

Therefore

dn=dn1+dn2

dn=32.5+38.2

dn=70.7kg

In conclusion,  the enthalpy change is

dn=70.7kg

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4 0
2 years ago
What does temperature measure?
nadya68 [22]
Average kinetic energy of the particles in the object
8 0
4 years ago
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What is formula for chromium (III) phosphate trihydrate and cobalt (II) phosphate octahydrate
Bezzdna [24]
The formula for  chromium (III) phosphate is CrPO4. This compound exists as a green crystal and as a hydrated form violet crystal having the formula of CrPO4•4H2O. The formula for cobalt(II) phosphate octahydrate is Co3(PO4)2•8H2O. It exists as an hydrated form.
4 0
3 years ago
If 196L of air at 1.0 atm is compressed to 26000ml, what is the new pressure
Elena L [17]

Answer:

7.5 atm

Explanation:

Initial pressure P1 = 1.0 ATM

Initial volume V1= 196 L

Final pressure P2= the unknown

Final volume V2= 26000ml or 26 L

From Boyle's law we have;

P1V1= P2V2

P2= P1V1/V2

P2= 1.0 × 196/26

P2 = 7.5 atm

Therefore, as the air is compressed, the pressure increases to 7.5 atm.

5 0
4 years ago
A lead sphere has a mass of 1.20 x 104 g, and its volume is 1.05 x 103 cm^3. Calculate the density of lead.
Hatshy [7]

Answer: The density of lead will be 11.42g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of lead=1.20\times 10^4g

Volume of lead =1.05\times 10^3cm^3

Putting in the values we get:

Density=\frac{1.20\times 10^4}{1.05\times 10^3}=11.42g/cm^3

Thus density of lead will be 11.42g/cm^3

4 0
3 years ago
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