PLEASE HELP!!!! 20 POINTS!!!

6. Find QR, if area and altitude PS of ∆PQR are given<br> ar(∆PQR) = 180 cm2, PS = 15

Slav-nsk [51]

Given:

Area and altitude PS of ∆PQR are ar(∆PQR) = 180cm² and PS = 15.

To find:

The measure of side QR.

Solution:

According to the given information, PS is an altitude of ∆PQR. It means QR is the base of ∆PQR.

We know that, the area of a triangle is

$Area=\dfrac{1}{2}\times Base\times Height$

$ar(\Delta PQR)=\dfrac{1}{2}\times QR\times PS$

Substituting the given values, we get

$180=\dfrac{1}{2}\times QR\times 15$

$180\times 2=QR\times 15$

$360=QR\times 15$

Divide both sides by 15.

$\dfrac{360}{15}=QR$

$24=QR$

Therefore, the measure of side QR is 24 cm.

3 0

3 years ago

9: The points (−2,5) and (5,−9) lie on the same line. What is its equation in slope-intercept form of this line? y= x +

iren2701 [21]

Answer:

y=negative 2x+1

Step-by-step explanation:

rise over run negative 14 over 7 equals negative 2 and the y intercept is 1

5 0

3 years ago

The radius of a circle is 1 kilometer. What is the area?Give the exact answer in simplest form.____ square kilometers

choli [55]

Ok, so;

Let me draw the figure here below:

We know that the area of a circle can be found using the next equation:

Area = πr².

Where r is the radius and π is a number.

So, the area of this circle, will be:

Area = π(1km)²

Area = π km²

7 0

1 year ago

A hypothesis test was used to see if less than 5% of all Americans would still drive to work if gas prices went above $10.00 a g

Kruka [31]

Answer:

The correct option is;

False

Step-by-step explanation:

Here, we note that the proportion of the test statistic which is used in the test is 5% and the P-value for the test is 0.03

The hypothesis test is meant to check if people will still drive to work when the gas prices are above $10.00 and the suggestion was that we can conclude that when the fuel price is above $5.00 everyone would still drive to work without a P-value for the test, hence we can not come to the stated conclusion.

8 0

3 years ago

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$

6 0

2 years ago