The equation of a line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so
we see that the slope is rise/run=3/4
3 points we see are (-4,-6), (0,-3) and (4,0)
we get the equations
y+6=3/4(x+4)
y+3=3/4(x+0)
y+0=3/4(x+4)
answer is the first equaiton
y+6=3/4(x+4)
Yes yes yes yes yes yes yes that is the makers Ik the answer it’s easy do you need help if so tell me
Complete question:
<span>Given the following diagram, if and mCOF = 150°, then mBOC = _____.
150°
90°
45°
30°
I attached a possible diagram that I found in a similar problem.
Using the diagram, I can see that </span>∠COF is supplementary to ∠BOC. This means that the sum of their angles is equal to 180°.
m∠COF + m∠BOC = 180°
m∠COF = 150°
m∠BOC = 180° - 150° = 30° Choice D.
Answer:
684.222222222
Step-by-step explanation:
Answer:
how many O's u would use would be 4
Step-by-step explanation: