Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean, 
= 90 and standard deviation, 
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z < 
) we get p(Z < 
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Answer:
450
Step-by-step explanation:
here is a fast way:
1- 75% = 75/100 = 3/4
2- 600 × (3/4) = 450
The score which is assigned from 1 to 4 by the teacher to each student for the project and is most likely to be is 3 with 0.48 probability.
<h3>
What is probability distribution?</h3>
Probability distribution is the statistical model which represent all the achievable and similar values of a random variable that it can possess in a specified range.
A teacher assigns a score from 1 to 4 to each student project. the table below shows the probability distribution of the scores for a randomly selected student.
- Probability distribution score: 1, 2, 3, 4,
- x probability: p(x) 0.06, 0.20, 0.48, 0.26
In the above data, the height probability of selection is 0.48. This probability belongs to the score 3.
Thus, the score which is assigned from 1 to 4 by the teacher to each student for the project and is most likely to be is 3 with 0.48 probability.
Learn more about the probability distribution here;
brainly.com/question/26615262
