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EleoNora [17]
3 years ago
12

Select the correct answer.

Mathematics
1 answer:
Elden [556K]3 years ago
5 0

Answer:

C. 3√5

Step-by-step explanation:

45 = 3 × 3 × 5 considering this the answer is C

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Please help me with this
Llana [10]
4 unknowns needs 4 equations. I'll call the unknown numbers a,b,c,d in that order left to right.

4 + a = b
a + b = c
b + c = d
c + d = 67

let's use substitution to get rid to combine equations and get rid of variables.
If a + b = c then a = c - b
4 + (c - b) = b
4 + c = 2b

If b + c = d then b = d - c
4 + c = 2(d - c)
4 + c = 2d - 2c
4 + 3c = 2d

then we have c + d = 67 so c = 67 - d

4 + 3(67 - d) = 2d
4 + 201 - 3d = 2d
205 = 5d
d = 41

Should be easy now, subtract backwards.

67 - 41 = 26
41 - 26 = 15
26 - 15 = 11
15 - 11 = 4

4, 11, 15, 26, 41, 67


3 0
3 years ago
Can someone help me.
Sauron [17]

Answer:

The answer to your question is: 20°

Step-by-step explanation:

Data

m∠XZY = 40

m∠XZB = 20

Process

1.- Find the measure of ∠ XAB

   ∠XAB = 40°   because AB ║ YZ

2.- Find the measure of ∠ZAB

     ∠ZAB + ∠XAB = 180

    ∠ZAB = 180 - ∠XAB

    ∠ZAB = 180 - 40

    ∠ZAB = 140°

3.- Find the measure of ∠ABZ

    The sum of the internal angles in a triangle equals 180°

     ∠AZB + ∠ZAB + ∠ABZ = 180

     20° + 140° + ∠ABZ = 180

     ∠ABZ = 180 - 20 - 140

    ∠ABZ = 20°

7 0
3 years ago
Howdoyouwrite<br> 36/50<br> as a percentage?
DENIUS [597]

Answer:

72%

Step-by-step explanation:

Divide 36 by 50 to get .72, and then convert it to a percentage

8 0
3 years ago
Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)
DiKsa [7]

Answer:

C

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. y'=(3\sin x)'=3\cos x. Differentiate again to get y''=(3\cos x)'=-3\sin x, then y''+y=-3\sin x+3\sin x=0\neq 3\sin x so this choice of y doesn't solve the equation.

B. y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x and y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x, then y''+y=10\sin x+6\cos x\neq 3\sin x so y is not a solution

C. y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x hence y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x. Then y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x so y is a solution.

D.y'=-3\sin x and y''=-3\cos x, then y''+y=0 thus y isn't a solution

E. y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x hence y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x. Then y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x then y is not a solution.

3 0
3 years ago
A rely race is 1/4 mile long and is run by 4-member teams. If each team member runs the same distance, what fraction of a mile d
NikAS [45]
0.0625

1/4 of a mile is 0.25
0.25 divided by 4 = 0.0625 each
8 0
3 years ago
Read 2 more answers
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