All categories

3 years ago

What time does the clock show? 12 1 11 10 3 - 8 4. 1 7 6 5

Mathematics

2 answers:

Scilla [17]3 years ago

5 0

7:59 I could be wrong so I’m sorry! Have a great day.

amm18123 years ago

3 0

Answer:

6:59

Step-by-step explanation:

Hour : Minute

Small hand is hour hand, large hand is minute hand. Minutes go by the small tic marks, where the hours go off of the numbers.

You might be interested in

Which equation represents a translation down 5 units on the parent function y=x? A) y = -x. B) Y=5x. C) Y = x. D) Y = x+ 5

Oduvanchick [21]

I learned something like this in maths today. I’m pretty sure it’s B) because you have all the variables already. So just put them together Y=5x. And I’m postitive that this is the answer. I hope this helped have a great rest of your day/night!

4 0

4 years ago

3. Bobbi bought 4 rolls of

sveta [45]

Answer:

400 x however long those ribbons are

Step-by-step explanation:

1 meter is 100 centimeters, and there are four rolls. so 4x100 equals 400, and you multiply that by the length that you didn't provide.

3 0

2 years ago

Can someone help plz

Vanyuwa [196]

Answer: -1.13

Step-by-step explanation: I counted from -1.1 to -1.15

6 0

3 years ago

Is it a parallelogram or not?

lions [1.4K]

Where is the picture

7 0

4 years ago

How to find the perimeter of the triangle

Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

Line AB

Let's start off by finding the distance of line AB.

We will use the formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to $d = \sqrt{(4--2)^{2}+(-3-5)^{2}}$ which in other words is $d = \sqrt{(4+2)^{2}+(-3-5)^{2}}$ .

Now we have to solve the parenthesis to get $d = \sqrt{(6)^{2}+(-8)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{36+64}$ .

Now we have to simplify the square root to $d = \sqrt{100}$ . In other words, that is $d = 10$ .

Line AB = 10

Line BC

Now let's find the distance of line BC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0-4)^{2}+(-6--3)^{2}}$ which in other words is $d = \sqrt{(0-4)^{2}+(-6+3)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(-4)^{2}+(-3)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{16+9}$ .

Now we have to simplify the square root to $d = \sqrt{25}$ . In other words, that is $d = 5$ .

Line BC = 5.

Line AC

Now let's fine the distance of line AC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0--2)^{2}+(-6-5)^{2}}$ which in other words is $d = \sqrt{(0+2)^{2}+(-6-5)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(2)^{2}+(-11)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{4+121}$ .

Now we have to simplify the square root to $d = \sqrt{125}$ . In other words, that is $d = 5\sqrt{5}$ . To round that, $d = 11.2$ .

Line AC = 11.2.

Perimeter of Triangle ABC

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0

3 years ago