Answer:
y=20
x=4
Step-by-step explanation:
Since you can plug the first 2 coordinates into the slope equation (
) you will get 4 for the slope so for the equation for the parallel line you would get y=4x+4 and since the x=4 you could plug that in and you would get y=20 and x=4
Answer:
The function y = -x whose reflection in the line y =x is itself.
Step-by-step explanation:
A reflection that maps every point of a figure to an image across a fixed line. Then the fixed line is called the line of reflection.
The reflection of the point (x,y) in the line y = x is the point (y, x).
Therefore, the function y = -x whose reflection in the line y =x is itself.
Symmetries of the function f(x)= -x is:
A function symmetric with respect to the y-axis is called an even function.
If f(-x) = f(x)
A function that is symmetric with respect to the origin is called an odd function.
if f(-x) = -f(x)
then, we must look at f(-x);
f(x) = -x
f(-x)= -(-x)= x = -f(x)
this function is symmetrical to with respect to origin.
Therefore, this function is an odd function.
I am not completely sure if tis is correct. I just took 16 and multiply them for the answer B and C. hope this can help you.
Answer:
Graph One.
Step-by-step explanation:
See below. The graph is in a straight line, also known as linear. The other graphs are not. Also, if you look at the range (y) of the tables, you can see the increase is linear as it is increasing by .5 (1/2) everytime.
Answer:
Step-by-step explanation:
![\sf \sqrt{-10} \\\\\sqrt{10} * \sqrt{-1} \\\\We \ know \ that \ \sqrt{-1} = i\\\\= \sqrt{10} i\\\\= \sqrt{2*5 } i \\\\Since \ 2 \ and \ 5 \ are \ not \ perfect \ squares, they \ cannot \ be \ simplified\ further.\\\\= \sqrt{10} i\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B-10%7D%20%5C%5C%5C%5C%5Csqrt%7B10%7D%20%2A%20%5Csqrt%7B-1%7D%20%5C%5C%5C%5CWe%20%5C%20know%20%5C%20that%20%5C%20%5Csqrt%7B-1%7D%20%3D%20i%5C%5C%5C%5C%3D%20%5Csqrt%7B10%7D%20i%5C%5C%5C%5C%3D%20%5Csqrt%7B2%2A5%20%7D%20i%20%5C%5C%5C%5CSince%20%5C%202%20%5C%20and%20%5C%205%20%5C%20are%20%5C%20not%20%5C%20perfect%20%5C%20squares%2C%20they%20%5C%20cannot%20%5C%20be%20%20%5C%20simplified%5C%20further.%5C%5C%5C%5C%3D%20%5Csqrt%7B10%7D%20i%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
