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bagirrra123 [75]
2 years ago
13

9 is 150% of what number​

Mathematics
1 answer:
damaskus [11]2 years ago
4 0

Answer:

13.5

Step-by-step explanation:

150% × 9 =

(150 ÷ 100) × 9 =

(150 × 9) ÷ 100 =

1,350 ÷ 100 =

13.5

My proof :

If 150% × 9 = 13.5 =>

Divide 13.5 by 9... ... And see if we get as a result: 150%.

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What's y=-4+15 in standard form
kotykmax [81]

Answer:

y=1.1×10¹

Step-by-step explanation:

y=-4+15

y=11

y=1.1×10¹

5 0
2 years ago
The area of this rectangle is 165 sq meters the width is 22 meters what’s is the perimeter?
Vesna [10]

Answer:

59 meters

Step-by-step explanation:

A=L*W

165=L*22

L=165/22=7.5

7.5=L

P=L+L+W+W

7.5+7.5+22+22=59


7 0
2 years ago
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


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kakasveta [241]

Answer:

No I didn't go

Step-by-step explanation:

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Three teachers burned calories dancing.
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Step-by-step explanation:

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